Donc ça marche:
SELECT c.name AS country_name, c.population AS country_population, SUM(ci.population) AS city_population, ROUND(100*(SUM(ci.population)/c.population)) AS city_population_percent
FROM country AS c
JOIN city AS ci
ON c.code = ci.countrycode
WHERE c.continent = 'Europe'
GROUP BY c.name
Mais je dois seulement saisir les valeurs city_population_percent supérieures à 30, alors j'essaye ceci:
SELECT c.name AS country_name, c.population AS country_population, SUM(ci.population) AS city_population, ROUND(100*(SUM(ci.population)/c.population)) AS city_population_percent
FROM country AS c
JOIN city AS ci
ON c.code = ci.countrycode
WHERE c.continent = 'Europe'
**AND ROUND(100*(SUM(ci.population)/c.population)) > 30**
GROUP BY c.name
Et c'est là que je reçois:
Code d'erreur 1111. Utilisation non valide de la fonction de groupe
Autrement dit, il échoue lorsque j'ajoute cette condition dans le WHERE
:
AND ROUND(100*(SUM(ci.population)/c.population)) > 30
Vous devez donc déplacer cette condition vers la clause AYANT
SELECT c.name AS country_name, c.population AS country_population, SUM(ci.population) AS city_population, ROUND(100*(SUM(ci.population)/c.population)) AS city_population_percent
FROM country AS c
JOIN city AS ci
ON c.code = ci.countrycode
WHERE c.continent = 'Europe'
GROUP BY c.name
HAVING ROUND(100*(SUM(ci.population)/c.population)) > 30
Vous utilisez des fonctions d'agrégation dans une clause where, ce que vous ne pouvez pas faire en SQL.
Utilisez à la place la clause AYANT :
WHERE c.continent = 'Europe'
GROUP BY c.name
HAVING ROUND(100*(SUM(ci.population)/c.population)) > 30