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Comment incrémenter une date / heure d'un jour?

Comment incrémenter le jour d'un datetime?

for i in range(1, 35)
    date = datetime.datetime(2003, 8, i)
    print(date)

Mais j'ai besoin de passer à travers des mois et des années correctement? Des idées?

pythondatetime
115
Pol
date = datetime.datetime(2003,8,1,12,4,5)
for i in range(5): 
    date += datetime.timedelta(days=1)
    print(date)
202
unutbu

L’incrémentation des dates peut être réalisée à l’aide d’objets timedelta:

import datetime

datetime.datetime.now() + datetime.timedelta(days=1)

Recherchez des objets timedelta dans le Python docs: http://docs.python.org/library/datetime.html

47
Piotr Duda

Toutes les réponses actuelles sont erronées dans certains cas car ils ne considèrent pas que les fuseaux horaires modifient leur décalage par rapport à UTC. Donc, dans certains cas, ajouter 24h est différent de l’ajout d’un jour calendaire.

Solution proposée

La solution suivante fonctionne pour Samoa et maintient l’heure locale constante.

def add_day(today):
    """
    Add a day to the current day.

    This takes care of historic offset changes and DST.

    Parameters
    ----------
    today : timezone-aware datetime object

    Returns
    -------
    tomorrow : timezone-aware datetime object
    """
    today_utc = today.astimezone(datetime.timezone.utc)
    tz = today.tzinfo
    tomorrow_utc = today_utc + datetime.timedelta(days=1)
    tomorrow_utc_tz = tomorrow_utc.astimezone(tz)
    tomorrow_utc_tz = tomorrow_utc_tz.replace(hour=today.hour,
                                              minute=today.minute,
                                              second=today.second)
    return tomorrow_utc_tz

Code testé

# core modules
import datetime

# 3rd party modules
import pytz


# add_day methods
def add_day(today):
    """
    Add a day to the current day.

    This takes care of historic offset changes and DST.

    Parameters
    ----------
    today : timezone-aware datetime object

    Returns
    -------
    tomorrow : timezone-aware datetime object
    """
    today_utc = today.astimezone(datetime.timezone.utc)
    tz = today.tzinfo
    tomorrow_utc = today_utc + datetime.timedelta(days=1)
    tomorrow_utc_tz = tomorrow_utc.astimezone(tz)
    tomorrow_utc_tz = tomorrow_utc_tz.replace(hour=today.hour,
                                              minute=today.minute,
                                              second=today.second)
    return tomorrow_utc_tz


def add_day_datetime_timedelta_conversion(today):
    # Correct for Samoa, but dst shift
    today_utc = today.astimezone(datetime.timezone.utc)
    tz = today.tzinfo
    tomorrow_utc = today_utc + datetime.timedelta(days=1)
    tomorrow_utc_tz = tomorrow_utc.astimezone(tz)
    return tomorrow_utc_tz


def add_day_dateutil_relativedelta(today):
    # WRONG!
    from dateutil.relativedelta import relativedelta
    return today + relativedelta(days=1)


def add_day_datetime_timedelta(today):
    # WRONG!
    return today + datetime.timedelta(days=1)


# Test cases
def test_samoa(add_day):
    """
    Test if add_day properly increases the calendar day for Samoa.

    Due to economic considerations, Samoa went from 2011-12-30 10:00-11:00
    to 2011-12-30 10:00+13:00. Hence the country skipped 2011-12-30 in its
    local time.

    See https://stackoverflow.com/q/52084423/562769

    A common wrong result here is 2011-12-30T23:59:00-10:00. This date never
    happened in Samoa.
    """
    tz = pytz.timezone('Pacific/Apia')
    today_utc = datetime.datetime(2011, 12, 30, 9, 59,
                                  tzinfo=datetime.timezone.utc)
    today_tz = today_utc.astimezone(tz)  # 2011-12-29T23:59:00-10:00
    tomorrow = add_day(today_tz)
    return tomorrow.isoformat() == '2011-12-31T23:59:00+14:00'


def test_dst(add_day):
    """Test if add_day properly increases the calendar day if DST happens."""
    tz = pytz.timezone('Europe/Berlin')
    today_utc = datetime.datetime(2018, 3, 25, 0, 59,
                                  tzinfo=datetime.timezone.utc)
    today_tz = today_utc.astimezone(tz)  # 2018-03-25T01:59:00+01:00
    tomorrow = add_day(today_tz)
    return tomorrow.isoformat() == '2018-03-26T01:59:00+02:00'


to_test = [(add_day_dateutil_relativedelta, 'relativedelta'),
           (add_day_datetime_timedelta, 'timedelta'),
           (add_day_datetime_timedelta_conversion, 'timedelta+conversion'),
           (add_day, 'timedelta+conversion+dst')]
print('{:<25}: {:>5} {:>5}'.format('Method', 'Samoa', 'DST'))
for method, name in to_test:
    print('{:<25}: {:>5} {:>5}'
          .format(name,
                  test_samoa(method),
                  test_dst(method)))

Résultats de test

Method                   : Samoa   DST
relativedelta            :     0     0
timedelta                :     0     0
timedelta+conversion     :     1     0
timedelta+conversion+dst :     1     1
7
Martin Thoma

Voici une autre méthode pour ajouter des jours à la date en utilisant relativedelta de dateutil.

from datetime import datetime
from dateutil.relativedelta import relativedelta

print 'Today: ',datetime.now().strftime('%d/%m/%Y %H:%M:%S') 
date_after_month = datetime.now()+ relativedelta(day=1)
print 'After a Days:', date_after_month.strftime('%d/%m/%Y %H:%M:%S')

Sortie:

Aujourd'hui: 25/06/2015 20:41:44

Après les jours: 01/06/2015 20:41:44

7
Atul Arvind