Liste de toutes les colonnes d'index et d'index dans la base de données SQL Server
Comment obtenir une liste de toutes les colonnes d'index et d'index dans SQL Server 2005+? Le plus proche que je pourrais obtenir est:
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
order by ic.key_ordinal
Ce qui n'est pas exactement ce que je veux.
Ce que je veux, c’est de lister tous les index définis par l’utilisateur, ( c’est-à-dire aucun index prenant en charge les contraintes uniques et les clés primaires ) avec toutes les colonnes (classées par leur affichage dans la définition de l’index) plus autant métadonnées que possible.
Vous pouvez consulter deux vues de catalogue "sys":
select * from sys.indexes
select * from sys.index_columns
Celles-ci vous donneront toutes les informations que vous pourriez souhaiter sur les index et leurs colonnes.
EDIT: Cette requête se rapproche beaucoup de ce que vous recherchez:
SELECT
TableName = t.name,
IndexName = ind.name,
IndexId = ind.index_id,
ColumnId = ic.index_column_id,
ColumnName = col.name,
ind.*,
ic.*,
col.*
FROM
sys.indexes ind
INNER JOIN
sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id
INNER JOIN
sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN
sys.tables t ON ind.object_id = t.object_id
WHERE
ind.is_primary_key = 0
AND ind.is_unique = 0
AND ind.is_unique_constraint = 0
AND t.is_ms_shipped = 0
ORDER BY
t.name, ind.name, ind.index_id, ic.index_column_id;
Vous pouvez utiliser le sp_helpindex pour afficher tous les index d'une table.
EXEC sys.sp_helpindex @objname = N'User' -- nvarchar(77)
Et pour tous les index, vous pouvez parcourir sys.objects pour obtenir tous les index de chaque table.
Aucune de ces personnes n'a fait le travail pour moi, mais ceci:
-- KDF9's concise index list for SQL Server 2005+ (see below for 2000)
-- includes schemas and primary keys, in easy to read format
-- with unique, clustered, and all ascending/descendings in a single column
-- Needs simple manual add or delete to change maximum number of key columns
-- but is easy to understand and modify, with no UDFs or complex logic
--
SELECT
schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName,
(CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK,
(CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+
(CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' '+ -- B=basic, C=Clustered, X=XML
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,1,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,2,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,3,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,4,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,5,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
(CASE INDEXKEY_PROPERTY(si.object_id,index_id,6,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+
'' as 'Type',
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,1) as Key1,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,2) as Key2,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,3) as Key3,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,4) as Key4,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,5) as Key5,
INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,6) as Key6
FROM sys.indexes as si
LEFT JOIN sys.objects as so on so.object_id=si.object_id
WHERE index_id>0 -- omit the default heap
and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables
and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams
ORDER BY SchemaName,TableName,IndexName
-------------------------------------------------------------------
-- or to generate creation scripts put a simple wrapper around that
SELECT SchemaName, TableName, IndexName,
(CASE pk
WHEN 'PK' THEN 'ALTER '+
'TABLE '+SchemaName+'.'+TableName+' ADD CONSTRAINT '+IndexName+' PRIMARY KEY'+
(CASE substring(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END)
ELSE 'CREATE '+
(CASE substring(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+
(CASE substring(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+
'INDEX '+IndexName+' ON '+SchemaName+'.'+TableName
END)+
' ('+
(CASE WHEN Key1 is null THEN '' ELSE Key1+(CASE substring(Type,4+1,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key2 is null THEN '' ELSE ', '+Key2+(CASE substring(Type,4+2,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key3 is null THEN '' ELSE ', '+Key3+(CASE substring(Type,4+3,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key4 is null THEN '' ELSE ', '+Key4+(CASE substring(Type,4+4,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key5 is null THEN '' ELSE ', '+Key5+(CASE substring(Type,4+5,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
(CASE WHEN Key6 is null THEN '' ELSE ', '+Key6+(CASE substring(Type,4+6,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+
')' as CreateIndex
FROM (
...
...listing SQL same as above minus the ORDER BY...
...
) as indexes
ORDER BY SchemaName,TableName,IndexName
----------------------------------------------------------
-- For SQL Server 2000 the following should work
-- change table names to sysindexes and sysobjects (no dots)
-- change object_id => id, index_id => indid,
-- change is_primary_key => (select count(constid) from sysconstraints as sc where sc.id=si.id and sc.status&15=1)
-- change is_unique => INDEXPROPERTY(si.id,si.name,'IsUnique')
-- change si.type => INDEXPROPERTY(si.id,si.name,'IsClustered')
-- remove all references to schemas including schema name qualifiers, and the XML type
-- add select where indid<255 and si.status&64=0 (to omit the text/image index and autostats)
Si vos noms incluent des espaces, ajoutez des crochets autour d'eux dans les scripts de création.
Lorsque la dernière colonne Key est entièrement nulle, vous savez qu'il n'en manque aucune.
Filtrer les clés primaires, etc. comme dans la requête initiale est trivial.
REMARQUE: soyez prudent avec cette solution car elle ne distingue pas les colonnes indexées et incluses.
--Court et doux:
SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema],
T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name],
I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key],
I.[is_unique_constraint], I.[fill_factor], I.[is_padded], I.[is_disabled], I.[is_hypothetical],
I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column]
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id]
INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id]
WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP'
ORDER BY T.[name], I.[index_id], IC.[key_ordinal]
Ce qui suit est similaire à sp_helpindex nomtable
select T.name as TableName, I.name as IndexName, AC.Name as ColumnName, I.type_desc as IndexType
from sys.tables as T inner join sys.indexes as I on T.[object_id] = I.[object_id]
inner join sys.index_columns as IC on IC.[object_id] = I.[object_id] and IC.[index_id] = I.[index_id]
inner join sys.all_columns as AC on IC.[object_id] = AC.[object_id] and IC.[column_id] = AC.[column_id]
order by T.name, I.name
J'ai eu besoin d'obtenir des index particuliers, leurs colonnes d'index et leurs colonnes incluses. Voici la requête que j'ai utilisée:
SELECT INX.[name] AS [Index Name]
,TBL.[name] AS [Table Name]
,DS1.[IndexColumnsNames]
,DS2.[IncludedColumnsNames]
FROM [sys].[indexes] INX
INNER JOIN [sys].[tables] TBL
ON INX.[object_id] = TBL.[object_id]
CROSS APPLY
(
SELECT STUFF
(
(
SELECT ' [' + CLS.[name] + ']'
FROM [sys].[index_columns] INXCLS
INNER JOIN [sys].[columns] CLS
ON INXCLS.[object_id] = CLS.[object_id]
AND INXCLS.[column_id] = CLS.[column_id]
WHERE INX.[object_id] = INXCLS.[object_id]
AND INX.[index_id] = INXCLS.[index_id]
AND INXCLS.[is_included_column] = 0
FOR XML PATH('')
)
,1
,1
,''
)
) DS1 ([IndexColumnsNames])
CROSS APPLY
(
SELECT STUFF
(
(
SELECT ' [' + CLS.[name] + ']'
FROM [sys].[index_columns] INXCLS
INNER JOIN [sys].[columns] CLS
ON INXCLS.[object_id] = CLS.[object_id]
AND INXCLS.[column_id] = CLS.[column_id]
WHERE INX.[object_id] = INXCLS.[object_id]
AND INX.[index_id] = INXCLS.[index_id]
AND INXCLS.[is_included_column] = 1
FOR XML PATH('')
)
,1
,1
,''
)
) DS2 ([IncludedColumnsNames])
Salut les gars, je n'y suis pas allé mais j'ai obtenu ce que je voulais dans la requête de l'auteur initial.
Je l'ai utilisé (sans conditions/filtres) pour mon besoin mais il a donné des résultats incorrects
Le problème principal était que résultats obtenait un produit croisé sans condition de jointure sur index_id
SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME
FROM SYS.TABLES T
INNER JOIN SYS.SCHEMAS S
ON T.SCHEMA_ID = S.SCHEMA_ID
INNER JOIN SYS.INDEXES I
ON I.OBJECT_ID = T.OBJECT_ID
INNER JOIN SYS.INDEX_COLUMNS IC
ON IC.OBJECT_ID = T.OBJECT_ID
INNER JOIN SYS.COLUMNS C
ON C.OBJECT_ID = T.OBJECT_ID
**AND IC.INDEX_ID = I.INDEX_ID**
AND IC.COLUMN_ID = C.COLUMN_ID
WHERE 1=1
ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL
Ce qui suit fonctionne sur SQL Server 2014/2016 ainsi que sur toute base de données Microsoft Azure SQL.
Produit un ensemble de résultats complet qui est facilement exportable vers Notepad/Excel pour le découpage en tranches et le découpage en dés et comprend
- Nom de la table
- Nom d'index
- Description de l'index
- Colonnes indexées - dans l'ordre
- Colonnes incluses - dans l'ordre
SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name'
,+ i.NAME AS 'index_name'
,LOWER(i.type_desc) + CASE
WHEN i.is_unique = 1
THEN ', unique'
ELSE ''
END + CASE
WHEN i.is_primary_key = 1
THEN ', primary key'
ELSE ''
END AS 'index_description'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 0
ORDER BY key_ordinal
FOR XML PATH('')
), 1, 2, '') AS 'indexed_columns'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 1
FOR XML PATH('')
), 1, 2, '') AS 'included_columns'
FROM sysindexes AS i1
INNER JOIN sys.indexes AS i ON i.object_id = i1.id
AND i.index_id = i1.indid
INNER JOIN sysobjects AS o ON o.id = i1.id
INNER JOIN sys.objects AS so ON so.object_id = o.id
AND is_ms_shipped = 0
INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id
WHERE so.type = 'U'
AND i1.indid < 255
AND i1.STATUS & 64 = 0 --index with duplicates
AND i1.STATUS & 8388608 = 0 --auto created index
AND i1.STATUS & 16777216 = 0 --stats no recompute
AND i.type_desc <> 'heap'
AND so.NAME <> 'sysdiagrams'
ORDER BY table_name
,index_name;
cela fonctionnera:
DECLARE @IndexInfo TABLE (index_name varchar(250)
,index_description varchar(250)
,index_keys varchar(250)
)
INSERT INTO @IndexInfo
exec sp_msforeachtable 'sp_helpindex ''?'''
select * from @IndexInfo
cela ne renvoie pas le nom de la table et vous obtiendrez des avertissements pour toutes les tables sans index. Si cela pose un problème, vous pouvez créer une boucle sur les tables ayant des index tels que
DECLARE @IndexInfoTemp TABLE (index_name varchar(250)
,index_description varchar(250)
,index_keys varchar(250)
)
DECLARE @IndexInfo TABLE (table_name sysname
,index_name varchar(250)
,index_description varchar(250)
,index_keys varchar(250)
)
DECLARE @Tables Table (RowID int not null identity(1,1)
,TableName sysname
)
DECLARE @MaxRow int
DECLARE @CurrentRow int
DECLARE @CurrentTable sysname
INSERT INTO @Tables
SELECT
DISTINCT t.name
FROM sys.indexes i
INNER JOIN sys.tables t ON i.object_id = t.object_id
WHERE i.Name IS NOT NULL
SELECT @MaxRow=@@ROWCOUNT,@CurrentRow=1
WHILE @CurrentRow<=@MaxRow
BEGIN
SELECT @CurrentTable=TableName FROM @Tables WHERE RowID=@CurrentRow
INSERT INTO @IndexInfoTemp
exec sp_helpindex @CurrentTable
INSERT INTO @IndexInfo
(table_name , index_name , index_description , index_keys)
SELECT
@CurrentTable , index_name , index_description , index_keys
FROM @IndexInfoTemp
DELETE FROM @IndexInfoTemp
SET @CurrentRow=@CurrentRow+1
END --WHILE
SELECT * from @IndexInfo
MODIFIER
si vous voulez, vous pouvez filtrer les données, voici quelques exemples (ceux-ci fonctionnent pour l'une ou l'autre méthode):
SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%primary key%'
SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%nonclustered%' AND index_description LIKE '%clustered%'
SELECT * FROM @IndexInfo WHERE index_description LIKE '%unique%'
with connect(schema_name,table_name,index_name,index_column_id,column_name) as
( select s.name schema_name, t.name table_name, i.name index_name, index_column_id, cast(c.name as varchar(max)) column_name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where index_column_id=1
union all
select s.name schema_name, t.name table_name, i.name index_name, ic.index_column_id, cast(connect.column_name + ',' + c.name as varchar(max)) column_name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id join connect on
connect.index_column_id+1 = ic.index_column_id
and connect.schema_name = s.name
and connect.table_name = t.name
and connect.index_name = i.name)
select connect.schema_name,connect.table_name,connect.index_name,connect.column_name
from connect join (select schema_name,table_name,index_name,MAX(index_column_id) index_column_id
from connect group by schema_name,table_name,index_name) mx
on connect.schema_name = mx.schema_name
and connect.table_name = mx.table_name
and connect.index_name = mx.index_name
and connect.index_column_id = mx.index_column_id
order by 1,2,3
Sur la base de la réponse acceptée et de deux autres questions 1 , 2 J'ai assemblé la requête suivante:
SELECT
QUOTENAME(t.name) AS TableName,
QUOTENAME(i.name) AS IndexName,
i.is_primary_key,
i.is_unique,
i.is_unique_constraint,
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) + CASE WHEN ic.is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 0
ORDER BY ic.key_ordinal
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') AS KeyColumns,
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 1
ORDER BY ic.index_column_id
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') AS IncludedColumns,
u.user_seeks,
u.user_scans,
u.user_lookups,
u.user_updates
FROM sys.tables AS t
INNER JOIN sys.indexes AS i ON t.object_id = i.object_id
LEFT JOIN sys.dm_db_index_usage_stats AS u ON i.object_id = u.object_id AND i.index_id = u.index_id
WHERE t.is_ms_shipped = 0
AND i.type <> 0
Cette requête renvoie des résultats tels que ci-dessous, qui affichent la liste des index, leurs colonnes et leur utilisation. Très utile pour déterminer quel index est plus performant que d’autres:
C'est une façon de sauvegarder dans les index. Vous pouvez utiliser SHOWCONTIG pour évaluer la fragmentation. Il listera tous les index de la base de données ou de la table, ainsi que des statistiques. Je tiens à mettre en garde que sur une base de données volumineuse, cela peut être long. Pour moi, l'un des avantages de cette approche est qu'il n'est pas nécessaire d'être un administrateur pour l'utiliser.
- Afficher les informations de fragmentation sur tous les index d'une base de données
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG WITH ALL_INDEXES
GO
... éteignez NOCOUNT lorsque vous avez terminé
- Afficher les informations de fragmentation sur tous les index d'une table
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG (authors) WITH ALL_INDEXES
GO
- Afficher les informations de fragmentation sur un index spécifique
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG (authors,aunmind)
GO
Puis-je hasarder une autre réponse à cette question saturée?
Ceci est un remaniement libéral de la réponse de @marc_s, mélangé à des éléments de @ Tim Ford, dans le but d'obtenir un ensemble de résultats plus propre et plus simple, ainsi qu'un affichage final et une commande répondant à mes besoins actuels.
SELECT
OBJECT_SCHEMA_NAME(t.[object_id],DB_ID()) AS [Schema],
t.[name] AS [TableName],
ind.[name] AS [IndexName],
col.[name] AS [ColumnName],
ic.column_id AS [ColumnId],
ind.[type_desc] AS [IndexTypeDesc],
col.is_identity AS [IsIdentity],
ind.[is_unique] AS [IsUnique],
ind.[is_primary_key] AS [IsPrimaryKey],
ic.[is_descending_key] AS [IsDescendingKey],
ic.[is_included_column] AS [IsIncludedColumn]
FROM
sys.indexes ind
INNER JOIN
sys.index_columns ic
ON ind.object_id = ic.object_id AND ind.index_id = ic.index_id
INNER JOIN
sys.columns col
ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN
sys.tables t
ON ind.object_id = t.object_id
WHERE
t.is_ms_shipped = 0
--ind.is_primary_key = 1 -- include or not pks, etc
--AND ind.is_unique = 0
--AND ind.is_unique_constraint = 0
ORDER BY
[Schema],
TableName,
IndexName,
[ColumnId],
ColumnName
Je suis venu avec celui-ci, qui me donne la vue d'ensemble exacte dont j'ai besoin. Ce qui est utile, c'est que vous obtenez une ligne par index dans laquelle les colonnes d'index sont agrégées.
select
o.name as ObjectName,
i.name as IndexName,
i.is_primary_key as [PrimaryKey],
SUBSTRING(i.[type_desc],0,6) as IndexType,
i.is_unique as [Unique],
Columns.[Normal] as IndexColumns,
Columns.[Included] as IncludedColumns
from sys.indexes i
join sys.objects o on i.object_id = o.object_id
cross apply
(
select
substring
(
(
select ', ' + co.[name]
from sys.index_columns ic
join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id
where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 0
order by ic.key_ordinal
for xml path('')
)
, 3
, 10000
) as [Normal]
, substring
(
(
select ', ' + co.[name]
from sys.index_columns ic
join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id
where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 1
order by ic.key_ordinal
for xml path('')
)
, 3
, 10000
) as [Included]
) Columns
where o.[type] = 'U' --USER_TABLE
order by o.[name], i.[name], i.is_primary_key desc
sur la base du code Tim Ford, voici la bonne réponse:
select tab.[name] as [table_name],
idx.[name] as [index_name],
allc.[name] as [column_name],
idx.[type_desc],
idx.[is_unique],
idx.[data_space_id],
idx.[ignore_dup_key],
idx.[is_primary_key],
idx.[is_unique_constraint],
idx.[fill_factor],
idx.[is_padded],
idx.[is_disabled],
idx.[is_hypothetical],
idx.[allow_row_locks],
idx.[allow_page_locks],
idxc.[is_descending_key],
idxc.[is_included_column],
idxc.[index_column_id]
from sys.[tables] as tab
inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id]
inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id]
inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id]
where tab.[name] Like '%table_name%'
and idx.[name] Like '%index_name%'
order by tab.[name], idx.[index_id], idxc.[index_column_id]
Notez simplement que si vous souhaitez utiliser l'une des requêtes ci-dessus pour écrire vos index, vous devez incorporer la colonne filter_definition de la table sys.indexes dans vos requêtes pour obtenir la définition de filtre d'index non clusterisés dans SQL 2008+
UN M
La solution ci-dessus est élégante, mais selon MS, INDEXKEY_PROPERTY est obsolète. Voir: http://msdn.Microsoft.com/en-us/library/ms186773.aspx
Dans Oracle
select CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME,CONNECYBY.COLUMN_NAME
from ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,COLUMN_POSITION,trim(',' from sys_connect_by_path(COLUMN_NAME,',')) COLUMN_NAME
from DBA_IND_COLUMNS
start with COLUMN_POSITION = 1
connect by TABLE_OWNER = prior TABLE_OWNER
and TABLE_NAME = prior TABLE_NAME
and INDEX_NAME = prior INDEX_NAME
and COLUMN_POSITION = prior COLUMN_POSITION + 1) CONNECYBY
join ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,max(COLUMN_POSITION) COLUMN_POSITION
from DBA_IND_COLUMNS
group by TABLE_OWNER,TABLE_NAME,INDEX_NAME) MAX_CONNECYBY
on ( CONNECYBY.SCHEMA_NAME = MAX_CONNECYBY.SCHEMA_NAME
and CONNECYBY.TABLE_NAME = MAX_CONNECYBY.TABLE_NAME
and CONNECYBY.INDEX_NAME = MAX_CONNECYBY.INDEX_NAME
and CONNECYBY.COLUMN_POSITION = MAX_CONNECYBY.COLUMN_POSITION)
order by CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME
Dans SQL Server Avec
CONNECTBY(SCHEMA_NAME,TABLE_NAME,INDEX_NAME,INDEX_COLUMN_ID,COLUMN_NAME)
as
( select SCHEMAS.NAME SCHEMA_NAME
, TABLES.NAME TABLE_NAME
, INDEXES.NAME INDEX_NAME
, INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID
, cast(COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME
from SYS.INDEXES
join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID)
join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID)
join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID
and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID)
join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID
and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID)
where INDEX_COLUMNS.INDEX_COLUMN_ID = 1
union all
select SCHEMAS.NAME SCHEMA_NAME
, TABLES.NAME TABLE_NAME
, INDEXES.NAME INDEX_NAME
, INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID
, cast(PRIOR.COLUMN_NAME + ',' + COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME
from SYS.INDEXES
join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID)
join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID)
join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID
and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID)
join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID
and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID)
join CONNECTBY as PRIOR on (SCHEMAS.NAME = PRIOR.SCHEMA_NAME
and TABLES.NAME = PRIOR.TABLE_NAME
and INDEXES.NAME = PRIOR.INDEX_NAME
and INDEX_COLUMNS.INDEX_COLUMN_ID = PRIOR.INDEX_COLUMN_ID + 1))
select CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME,CONNECTBY.COLUMN_NAME
from CONNECTBY
join ( select SCHEMA_NAME
, TABLE_NAME
, INDEX_NAME
, MAX(INDEX_COLUMN_ID) INDEX_COLUMN_ID
from CONNECTBY
group by SCHEMA_NAME,TABLE_NAME,INDEX_NAME) MAX_CONNECTBY
on (CONNECTBY.SCHEMA_NAME = MAX_CONNECTBY.SCHEMA_NAME
and CONNECTBY.TABLE_NAME = MAX_CONNECTBY.TABLE_NAME
and CONNECTBY.INDEX_NAME = MAX_CONNECTBY.INDEX_NAME
and CONNECTBY.INDEX_COLUMN_ID = MAX_CONNECTBY.INDEX_COLUMN_ID)
order by CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME
Étant donné que votre profil indique que vous utilisez .NET, vous pouvez utiliser SMO (Server Managed Objects) par programme ... sinon, aucune des réponses ci-dessus n’est fantastique.
La requête ci-dessous inclut toutes les informations pertinentes pour les index définis par l'utilisateur (pas d'index pour les contraintes uniques et les clés primaires) avec toutes les colonnes:
SELECT I.name as IndexName,
CASE WHEN I.is_unique = 1 THEN 'Yes' ELSE 'No' END as 'Unique',
I.type_desc COLLATE DATABASE_DEFAULT as Index_Type,
'[' + SCHEMA_NAME(T.schema_id) + ']' as 'Schema',
'[' + T.name + ']' as TableName,
STUFF((SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END
FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id
WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id
FOR XML PATH('')), 1, 2, '') as Key_Columns,
Included_Columns,
I.filter_definition,
CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END as PAD_INDEX,
CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END as [Statistics_Norecompute],
CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) as [Fillfactor],
CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END as [Ignore_Dup_Key],
CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END as [Allow_Row_Locks],
CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END [Allow_Page_Locks]
FROM sys.indexes I INNER JOIN
sys.tables T ON T.object_id = I.object_id INNER JOIN
sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN
sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN
sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN
(SELECT * FROM
(SELECT IC2.object_id, IC2.index_id,
STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN
sys.columns C ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
AND IC1.is_included_column = 1
WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id
GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('')
), 1, 2, '') as Included_Columns
FROM sys.index_columns IC2
GROUP BY IC2.object_id, IC2.index_id) tmp1
WHERE Included_Columns IS NOT NULL
) tmp2
ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id
WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0;
En prime, la requête ci-dessous est formatée pour écrire les scripts create index et drop index:
SELECT I.name as IndexName,
-- Uncommnent line below to include checking for index exists as part of the script
--'IF NOT EXISTS (SELECT name FROM sysindexes WHERE name = '''+ I.name +''') ' +
'CREATE ' + CASE WHEN I.is_unique = 1 THEN ' UNIQUE ' ELSE '' END +
I.type_desc COLLATE DATABASE_DEFAULT + ' INDEX [' +
I.name + '] ON [' + SCHEMA_NAME(T.schema_id) + '].[' + T.name + '] (' + STUFF(
(SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END
FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id
WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id
FOR XML PATH('')), 1, 2, '') + ') ' +
ISNULL(' INCLUDE (' + IncludedColumns + ') ', '') +
ISNULL(' WHERE ' + I.filter_definition, '') +
'WITH (PAD_INDEX = ' + CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END +
', STATISTICS_NORECOMPUTE = ' + CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END +
', SORT_IN_TEMPDB = OFF' +
', FILLFACTOR = ' + CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) +
', IGNORE_DUP_KEY = ' + CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END +
', ONLINE = OFF' +
', ALLOW_ROW_LOCKS = ' + CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END +
', ALLOW_PAGE_LOCKS = ' + CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END +
') ON [' + DS.name + '];' + CHAR(13) + CHAR(10) + 'GO' as [CreateIndex],
'DROP INDEX ['+ I.name +'] ON ['+ SCHEMA_NAME(T.schema_id) +'].['+ T.name +'];' +
CHAR(13) + CHAR(10) + 'GO' AS [DropIndex]
FROM sys.indexes I INNER JOIN
sys.tables T ON T.object_id = I.object_id INNER JOIN
sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN
sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN
sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN
(SELECT * FROM
(SELECT IC2.object_id, IC2.index_id,
STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN
sys.columns C ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
AND IC1.is_included_column = 1
WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id
GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('')
), 1, 2, '') as IncludedColumns
FROM sys.index_columns IC2
GROUP BY IC2.object_id, IC2.index_id) tmp1
WHERE IncludedColumns IS NOT NULL
) tmp2
ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id
WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0
Pour les colonnes uniques par index:
select s.name, t.name, i.name, i.index_id,c.name,c.column_id
from sys.schemas s
inner join sys.tables t on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
and ic.index_id=i.index_id
inner join sys.columns c on c.object_id = t.object_id
and ic.column_id = c.column_id
where i.object_id = object_id('previous.account_1')
order by index_id,column_id
Tout d'abord, veuillez noter que toutes les requêtes ci-dessus peuvent manquer ou incorporer à tort les colonnes INCLUDE des index. Il manque également dans certains cas le bon ordre et/ou l’option ASC/DESC des colonnes.
Modifié la requête ci-dessus par jona. Par ailleurs, dans la plupart des bases de données que j'utilise, j'installe ma propre fonction d'agrégation CLR CONCATENATE. Le code ci-dessous dépend donc de la présence de ce type. Les instructions SQL ci-dessus réduisent à beaucoup plus maintenable:
SELECT
s.[name] AS [schema_name]
, t.[name] AS [table_name]
, i.[name] AS [index_name]
, dbo.Concatenate(CASE WHEN ic.[key_ordinal] > 0 AND ic.[is_descending_key] = 1 THEN c.[name] + ' DESC' WHEN key_ordinal > 0 THEN c.[name] ELSE NULL END,',',1) AS [columns]
, dbo.Concatenate(CASE WHEN ic.[is_included_column] = 1 THEN c.[name] ELSE NULL END,',',1) AS [includes]
FROM
sys.tables t
INNER JOIN
sys.schemas s ON t.[schema_id] = s.[schema_id]
INNER JOIN
sys.indexes i ON i.[object_id] = t.[object_id]
INNER JOIN
sys.index_columns ic ON ic.[object_id] = t.[object_id] AND ic.index_id = i.index_id
INNER JOIN
sys.columns c ON c.[object_id] = t.[object_id] AND ic.column_id = c.column_id
GROUP BY
s.[name]
, t.[name]
, i.[name]
ORDER BY
s.[name]
, t.[name]
, i.[name]
Il y a beaucoup de agrégats de concaténation là-bas si votre environnement autorise l'ajout de fonctions basées sur le CLR.
À l'aide de SQL Server 2016, cela donne une liste complète de tous les index, avec un vidage inclus de chaque table afin que vous puissiez voir le lien entre les tables. Il affiche également les colonnes incluses dans les index de couverture:
select t.name TableName, i.name IdxName, c.name ColName
, ic.index_column_id ColPosition
, i.type_desc Type
, case when i.is_primary_key = 1 then 'Yes' else '' end [Primary?]
, case when i.is_unique = 1 then 'Yes' else '' end [Unique?]
, case when ic.is_included_column = 0 then '' else 'Yes - Included' end [CoveredColumn?]
, 'indexes >>>>' [*indexes*], i.*, 'index_columns >>>>' [*index_columns*]
, ic.*, 'tables >>>>' [*tables*]
, t.*, 'columns >>>>' [*columns*], c.*
from sys.index_columns ic
join sys.tables t on t.object_id = ic.object_id
join sys.columns c on c.object_id = t.object_id and c.column_id = ic.column_id
join sys.indexes i on i.object_id = t.object_id and i.index_id = ic.index_id
order by TableName, IdxName, ColPosition
Voici le meilleur moyen de le faire:
SELECT sys.tables.object_id, sys.tables.name as table_name, sys.columns.name as column_name, sys.indexes.name as index_name,
sys.indexes.is_unique, sys.indexes.is_primary_key
FROM sys.tables, sys.indexes, sys.index_columns, sys.columns
WHERE (sys.tables.object_id = sys.indexes.object_id AND sys.tables.object_id = sys.index_columns.object_id AND sys.tables.object_id = sys.columns.object_id
AND sys.indexes.index_id = sys.index_columns.index_id AND sys.index_columns.column_id = sys.columns.column_id)
AND sys.tables.name = 'your_table_name'Je préfère utiliser des jointures implicites car il m'est beaucoup plus facile de comprendre. Vous pouvez supprimer la référence object_id car vous n'en aurez peut-être pas besoin.
À votre santé.
Ceci est à moi, fonctionne sur un schéma par défaut mais il peut être facilement amélioré Il donne 3 colonnes avec SQLQueries - Create/Drop/Rebuild (aucune réorganisation)
Question:
SELECT
'CREATE ' +
CASE WHEN is_primary_key=1 THEN 'CLUSTERED'
WHEN is_primary_key=0 and is_unique_constraint=0 THEN 'NONCLUSTERED'
WHEN is_primary_key=0 and is_unique_constraint=1 THEN 'UNIQUE' END
+ ' INDEX ' +
QUOTENAME(i.name) + ' ON ' +
QUOTENAME(t.name) + ' ( ' +
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) + CASE WHEN ic.is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 0
ORDER BY ic.key_ordinal
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') + ' ) ' -- keycols
+ COALESCE(' INCLUDE ( ' +
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 1
ORDER BY ic.index_column_id
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') + ' ) ', -- included cols
'') as [Create],
'DROP INDEX ' + QUOTENAME(i.name) + ' ON ' + QUOTENAME(t.name) as [Drop],
'ALTER INDEX ' + QUOTENAME(i.name) + ' ON ' +QUOTENAME(t.name) + ' REBUILD ' as [Rebuild]
FROM sys.tables AS t
INNER JOIN sys.indexes AS i ON t.object_id = i.object_id
LEFT JOIN sys.dm_db_index_usage_stats AS u ON i.object_id = u.object_id AND i.index_id = u.index_id
WHERE t.is_ms_shipped = 0
AND i.type <> 0
order by QUOTENAME(t.name), is_primary_key desc
Sortie
Create Drop Rebuild
-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
CREATE CLUSTERED INDEX [PK_Table1] ON [Table1] ( [Tab1_ID] ) DROP INDEX [PK_Table1] ON [Table1] ALTER INDEX [PK_Table1] ON [Table1] REBUILD
CREATE UNIQUE INDEX [IX_Table1_Name] ON [Table1] ( [Tab1_Name] ) DROP INDEX [IX_Table1_Name] ON [Table1] ALTER INDEX [IX_Table1_Name] ON [Table1] REBUILD
CREATE NONCLUSTERED INDEX [IX_Table2] ON [Table2] ( [Tab2_Name], [Tab2_City] ) INCLUDE ( [Tab2_PhoneNo] ) DROP INDEX [IX_Table2] ON [Table2] ALTER INDEX [IX_Table2] ON [Table2] REBUILD
Solution de travail pour SQL Server 2014. Je n'ai inclus ici que quelques champs de sortie, mais n'hésitez pas à en ajouter autant que vous le souhaitez.
SELECT
o.object_id AS objectId
,o.name AS objectName
,i.index_id AS indexId
,i.name AS indexName
,i.type_desc AS typeDesc
,ic.index_column_id AS indexColumnId
,ic.key_ordinal AS keyOrdinal
,ic.is_included_column AS isIncludedColumn
,ic.column_id AS columnId
,c.name AS columnName
FROM {database}.sys.objects AS o
INNER JOIN {database}.sys.columns AS c ON
c.object_id = o.object_id
AND o.type = 'U'
INNER JOIN {database}.sys.indexes AS i ON
i.object_id = o.object_id
INNER JOIN {database}.sys.index_columns AS ic ON
ic.object_id = i.object_id
AND ic.index_id = i.index_id
AND ic.column_id = c.column_id
ORDER BY
o.object_id
,i.index_id
,ic.index_column_id
J'ai utilisé la requête suivante lorsque j'avais cette exigence ...
SELECT
TableName = t.name,
ColumnId = col.column_id,
ColumnName = col.name,
DataType = ty.name,
MaxSize = ty.max_length,
IsNullable = CASE WHEN (col.is_nullable = 1) THEN 'Y' END,
IsIdentity = CASE WHEN (col.is_identity = 1) THEN 'Y' END,
IsPrimaryKey = CASE WHEN (ic.column_id = col.column_id) THEN 'Y' END,
IsForeignKey = CASE WHEN (fkc.parent_column_id = col.column_id) THEN 'Y' END,
IsDefault = CASE WHEN (dc.parent_column_id = col.column_id) THEN 'Y' END
FROM
sys.tables t
INNER JOIN
sys.columns col ON t.object_id = col.object_id
LEFT JOIN
sys.indexes ind ON t.object_id = ind.object_id
LEFT JOIN
sys.index_columns ic ON ic.index_id=ind.index_id AND ic.object_id = col.object_id and ic.column_id = col.column_id
LEFT JOIN sys.foreign_key_columns fkc
ON fkc.parent_object_id = col.object_id AND fkc.parent_column_id=col.column_id
LEFT JOIN sys.default_constraints dc
ON dc.parent_object_id = col.object_id AND dc.parent_column_id=col.column_id
LEFT JOIN
sys.types ty on ty.user_type_id = col.user_type_id
WHERE
--t.name='<TABLENAME>'
t.schema_id = 10 --SCHEMA ID
AND ind.is_primary_key=1
ORDER BY
t.name, ColumnId